Sets are defined as a well-defined collection of objects. A set without any element is termed as an empty set. A set comprising of definite elements is termed as a finite set whereas if the set has an indefinite number of elements it is termed an infinite set. Two sets P and Q are equal if they have exactly the same number of elements. A set P is a subset of a set Q if all the elements of P are also an element of Q. A power set [A(P)] of a set P comprising of all subsets of P. The union of sets P and Q is a set comprising of all elements which are either in sets P or Q. The intersection of sets P and Q is a set comprising of all common elements of sets P and Q. Similarly, the difference of sets P and Q in the same order is a set comprising of elements belonging to P but not Q.
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Important Equations
- For any two sets P and Q,
- (P ∪ Q)′ = P′ ∩ Q′
- (P ∩ Q)′ = P′ ∪ Q′
- If P and Q are finite sets such that P ∩ Q = φ, then n (P ∪ Q) = n (P) + n (Q).
- If P ∩ Q ≠ φ, then
n (P ∪ Q) = n (P) + n (Q) – n (P ∩ Q)
- n (P ∪ Q ∪ R) = n(P) + n(Q) + n(R) – n(P ∩ Q) – n(P ∩ Q) – n(P ∩ Q ) + n(P ∩ Q ∩ R)
- If P is a subset of set U (Universal Set), then its complement (P′) is also a subset of Universal Set (U).
Also Read: NCERT Solutions for Class 11 Maths Chapter 1
Some Properties of Operation of Intersection
- P ∩ Q = Q ∩ P (Commutative law).
- (P ∩ Q) ∩ R = P ∩ (Q ∩ R) (Associative law).
- φ ∩ P = φ, U ∩ P = P.
- P ∩ P = P (Idempotent law).
- P ∩ (Q ∪ R) = (P ∩ Q) ∪ (P ∩ Q) (Distributive law).
Also Read: Set Theory
Some Properties of the Operation of Union
- P ∪ Q = Q ∪ P (Commutative law).
- (P ∪ Q) ∪ R = P ∪ ( Q ∪ R) (Associative law).
- P ∪ φ = P (Law of the identity element).
- U ∪ P = U (Law of U).
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Sets Class 11 Practice Questions
- For any set P and Q, Show that P = (P ∩ Q) ∪ (P – Q) and P ∪ (Q – P) = (P ∪ Q)
- Using the properties of sets, Prove
- P ∪ ( P ∩ Q) = P
- P ∩ (P ∪ Q) = P
- Prove that, P ∩ Q = P ∩ R need not imply Q = R.
- If P and Q are two sets and P ∩ Z = Q ∩ Z = φ and P ∪ Z = Q ∪ Z for some set Z, Prove that P = Q.
- Find sets M, N and O such that M ∩ N, N ∩ O, and M ∩ O are non-empty sets and M ∩ N ∩ O = φ.
- Let M, N, and O are three sets such that M ∪ N = M ∪ O and M ∩ N = M ∩ O. Prove that N = O.
- If P ⊂ Q, then prove that R – Q ⊂ Q – P.
- If A(n) = A(m), then, prove that m = n.
Also refer: NCERT Exemplar for class 11 Maths Chapter 1
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